Basically, I want it to look for ROCKET. Java regex to match word with nonboundaries – contain word example. Here's one way to implement some equivalent to the "AND"ing of regexp needed for this specific application. Method 1: grep for first and last character. Ask Question Asked 10 years, 7 months ago. The first backreference will contain the word the line actually contains. … If a line can meet any out of series of requirements, simply use alternation in the regular expression. *bee$ The negative look ahead will ensure that the expression will not match if the phrase contains … If it contains … Check out my new REGEX COOKBOOK about the most commonly used (and most wanted) regex . If you want to match a word A in a string and not to match a word B. UPDATE! * $ matches a complete line of text that contains any of the words “one”, “two” or “three”. A compatible regular expression with basic syntax only would be: [0-8]\d\d|\d[0-8]\d|\d\d[0-8] This does also match any three digits sequence that is not 999. Regular expression for a string containing one word but not another. You could use this regular expression (which uses a negative lookahead): (?!.*like)^sting. Word-constituent characters are letters, digits, and the underscore. So, 'input damian whatever' is a match, while 'input damian type whatever' is not. ^. regular expression to allow spaces between words, This regex works great but it doesn't allow for spaces between words. The regex should match ROCKET in upper or lower cases, and with or without punctuation, but not when part of another word. Similarly, it must be either at the end of the line or followed by a non-word constituent character. In this case the string is virus. Hi fristi, I want it to match any whole sentence that begins with, ends with or contains a string. I have a two pets - … A simple cheatsheet by examples. * \b (one | two | three) \b. Greetings, I have a problem with finding a regex pattern that should match any text containing a group of letters, and in the same time it does not contain another group of letters. For example: If you have a text: 1. Example 1. 3. Suppose you want to validate so that a phrase starts with "string" and ends with "bee", but does not contain "like". The following example calls the Matches(String, String) method to identify any word in a sentence that ends in "es", and then calls the Matches(String, String, RegexOptions) method to perform a case-insensitive comparison of the pattern with the input string. Suppose, you want to match “java” such that it should be able to match words like “javap” or “myjava” or “myjavaprogram” i.e. Dear colleagues, I am trying to write regex, that can match one word with uppercase letters or multiple words, separated by whitespace. For those interested in the details, the technique employed is to convert the regular expression that matches the word into a finite automaton, then invert the automaton by changing every acceptance state to non-acceptance and vice versa, and then converting the resulting FA back to a regular expression. Regular expressions (regex or … Active 1 year ago. I want to create an expression that will identify any URL that contains the string selector=size but does NOT contain details.cfm. We can grep an exact match by putting a regex match of beginning(^) and ending($) char. Iterating a file line by line, I need to extract the lines containing the word 'input', AND not containing the word 'type'. Regex match string containing word. ^[a-zA-Z0- 9_]*$ A string that contains multiple spaces in between words, “Hello World”. I've been trying to get a specific regex working but I can't get it to do what I need. 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